 
 
 
 
 
 
 
  
Following similar precept we can do color masking by removing the effect of that particular colour. I will show you the masking for red as the masking for other colours is obvious.
pixel.red =0x00; //mask red. pixel.green |=0; //no change. pixel.blue |=0; //no change.
The routine below modifies the image removing the said
component [color takes values of either [r/R] or  [g/G]  or [b/B]]
and processes it.[ see ![[*]](crossref.png) ] . This code yielded figures 
like this.
] . This code yielded figures 
like this.
#include<gtk/gtk.h>
void colormask_picture(GdkPixbuf *pb,gchar color)
{
  int ht,wt;
  int i=0,j=0;
  int rowstride=0;  
  int bpp=0;
  gchar *pixel;
  if(gdk_pixbuf_get_bits_per_sample(pb)!=8)   //we handle only 24 bit images.
  	return;                               //look at 3 bytes per pixel.
  bpp=3;	         	  //getting attributes of height,
  ht=gdk_pixbuf_get_height(pb);   //width, and bpp.Also get pointer
  wt=gdk_pixbuf_get_width(pb);	  //to pixels.
  pixel=gdk_pixbuf_get_pixels(pb);
  rowstride=wt*bpp;
  for(i=0;i<ht;i++)		//iterate over the height of image.
    for(j=0;j<rowstride;j+=bpp)   //read every pixel in the row.skip
				//bpp bytes 
      {	
      
      //access pixel[i][j] as
      // pixel[i*rowstride + j]
      //access red,green and blue as
	switch(color)
	  {
	  case 'r':
	  case 'R':
	    pixel[i*rowstride + j+0]=0x00;//mask red;
	    break;
	  case 'g':
	  case 'G':
	    pixel[i*rowstride + j+1]=0x00;//mask green
	    break;
	  case 'b':
	  case 'B':
	    pixel[i*rowstride + j+2]=0x00;//mask blue;
	  default:
	    pixel[i*rowstride + j+2]=0x00;//mask blue;
	  }	    
      }
  return;
}
% <!-- provide link here-->
% complete working example with glue code in example_colormask.c